1/2(2x-3)^2=10

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Solution for 1/2(2x-3)^2=10 equation: 



1/2(2x-3)^2=10

We move all terms to the left:

1/2(2x-3)^2-(10)=0



Domain of the equation: 2(2x-3)^2!=0

x∈R



We multiply all the terms by the denominator


-10*2(2x-3)^2+1=0

Wy multiply elements

-20x(2+1=0

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